Sederhanakanlah
[tex]3a {}^{2} + 4a + 3 - 2a {}^{2} + 2a[/tex]
![]()
[tex]3a {}^{2} + 4a + 3 - 2a {}^{2} + 2a[/tex]
[tex] {3a}^{2} + 4a + 3 - {2a}^{2} + 2a \\ = ( {3a}^{2} - {2a}^{2} ) + (4a + 2a) + 3 \\ = {a}^{2} + 6a + 3[/tex]
[tex]{ \boxed{ \boxed{ \bold{ \huge{ \mathfrak{ \red{m}{ \orange{a}{ \green{g}{ \blue{h}{ \purple{f}{ \red{i}{ \orange{24}}}}}}}}}}}}}[/tex]
Jawaban:
3a² + 4a + 3 - 2a² + 2a
= 3a²-2a² + 4a +2a + 3
= 1a² + 6a + 3
= a² + 6a + 3
[answer.2.content]
