Hitunglah pH (a) larutan HCl 1,0x10-3M dan (b) larutan Ba(OH)2 0,020M!
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Rumus :
mmol = V × M
pH = -log [H+]
pH = 14-log [OH-]
[H+] atau [OH-] = a.Ma atau b.Mb
Jawab :
A.
pH = -log [1 × 10-³ M]
= 3-log 1
B.
pH = 14 - (-log [2 . 2 × 10-² M])
= 14 - (-log [4 × 10-² M])
= 10+log 2
[answer.2.content]
